Q.4. The taxi fare in a city is as follows: For the first kilometre, the fare is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw its graph.

Solution:

Let total distance covered be x and the total fare be y.

ATQ,

y = 8 + 5(x-1)

⇒ y = 8 + 5x - 5

⇒ y = 5x + 3

We can tabulate the points on the line as follows,

x

0

-1

y

3

-2

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