Q.4. The taxi fare in a city is as follows: For the first kilometre, the fare is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw its graph.
Solution:
Let total distance covered be x and the total fare be y.
ATQ, y = 8 + 5(x1) ⇒ y = 8 + 5x  5 ⇒ y = 5x + 3 We can tabulate the points on the line as follows,
