Q.3. If the point (3, 4) lies on the graph of the equation 3y = ax + 7, find the value of a.

Solution:

The point (3, 4) lies on the graph of the equation 3y = ax + 7.

Putting x = 3 and y = 4, we get,

3×4 = a×3 + 7

⇒ 12 = 3a + 7

⇒ 3a = 12 - 7

⇒ a = $\frac{5}{3}$