**Q.2.** Write four solutions for each of the following equations:

(i) 2x + y = 7 (ii) πx + y = 9 (iii) x = 4y

**Solution:**

(i) Given, 2x + y = 7

⇒ y = 7 - 2x

Put x = 0 ⇒ y = 7 - 2 × 0 ⇒ y = 7

⇒ (0, 7) is the solution.

We can similarly tabulate the four solutions as follows,

x |
0 |
1 |
2 |
3 |

y |
7 |
5 |
3 |
1 |

Hence, the four solutions of the equation 2x + y = 7 could be (0, 7), (1, 5), (2, 3) and (3, 1).

(ii) πx + y = 9 ⇒ y = 9 - πx

x |
0 |
1 |
2 |
3 |

y |
9 |
9 - π |
9 - 2π |
9 - 3π |

The four solutions of the equation πx + y = 9 could be (0, 9), (1, 9-π), (2, 9-2π) and (3, 9-3π).

(iii) x = 4y

x |
0 |
4 |
8 |
12 |

y |
0 |
1 |
2 |
3 |

The four solutions of the equation πx + y = 9 may be (0, 0), (4, 1), (8, 2) and (12, 3).