Q.4. Represent $\sqrt{9.3}$ on the number line.

Solution:

1. Draw a line segment of unit 9.3. Extend it to C so that BC = 1 unit.

2. Now, AC = 10.3 units. Find the midpoint of AC. Let it be O.

3. Draw a semi circle with radius OA = OC and centre O.

4. Draw a perpendicular to AC at point B which intersects the semicircle at D. Join OD.

5. Now, OBD is a right angled triangle. The length of BD is $\sqrt{9.3}$.

6. Taking BD as radius and B as centre draw an arc which cuts the line segment AC at E. Now BE is equal to $\sqrt{9.3}$.