**Q.4.** Represent $\sqrt{9.3}$ on the number line.

**Solution:**

- Draw a line segment of unit 9.3. Extend it to C so that BC = 1 unit.
- Now, AC = 10.3 units. Find the midpoint of AC. Let it be O.
- Draw a semi circle with radius OA = OC and centre O.
- Draw a perpendicular to AC at point B which intersects the semicircle at D. Join OD.
- Now, OBD is a right angled triangle. The length of BD is $\sqrt{9.3}$.
- Taking BD as radius and B as centre draw an arc which cuts the line segment AC at E. Now BE is equal to $\sqrt{9.3}$.